Submitted by Adam Johnson / Harvey Mudd College on Sun, 03/06/2011 - 23:21

Not to ding Miessler and Tarr, I love the book.  But i'm finding more typos than usual in the 4th ed. Someone suggested I create a forum post to log them to be helpful.  Here are the ones I can think of right now:


problem 12.21 (page 482):  R. L. Rheingold?? should be A. L. Rheingold.

problem 6.27 (page 218): NH3   CH3NH2(CH3)2  NH(CH3)3    N; certainly supposed to be  NH3   CH3NH2   (CH3)2NH   (CH3)3N


Add others in the comments!

Maggie Geselbracht / Reed College

Here's one that my students picked up on! 

In Chapter 8, on page 260 and 261 in the discussion of the Frost diagrams for oxygen, they were confused by the shape of the curve in Figure 8.5a for the acidic solution.  Why isn't the point for the -1 oxidation state a positive value since the y-axis is in units of -nFE˚ and the E˚ for the reduction of O2 to H2O2 is listed as -0.0695 on pg. 260?  Good question!

So, I dug out my copy of the 3rd edition to compare these pages (pg. 246 in M&T, 3rd edition).  In the 3rd edition the E˚ for the reduction of O2 to H2O2 is listed as +0.695, which is consistent with the Frost diagram.  Correct the E˚ in the 4th edition to +0.695 and all is well!

Since I did not lecture on Frost diagrams at all, but expected them to read and understand this for a Clicker Quiz, I was happy to see that at least some of the students understood the concept enough to spot the error!

Mon, 03/07/2011 - 18:05 Permalink
Anne Bentley / Lewis & Clark College

Thanks, Adam.  I just assigned 6.27 as an optional extra problem, but I think my eye ran too quickly over the problem to pick up the typo.


I distinctly remember drawing a negative sign in to my 4th ed textbook in the past month or so.  I will post that typo if I can find it.


Wed, 03/09/2011 - 14:11 Permalink
Adam Johnson / Harvey Mudd College
problem 13.48 gives characterization data for the Cr complex, and NOT the Mo complex as stated in the problem.  The difference in IR and NMR shifts is minimal between the two and it wouldn't be a big issue, excpet the CHN analyis is way off.  I would have missed this but I went to the original paper (by VIPEr user Paul Fischer, no less!) to read up on it.
Fri, 03/18/2011 - 15:54 Permalink
Anne Bentley / Lewis & Clark College

Major errors with an end-of-chapter-7 problem were passed along into edition 4.  The problem is number 7.19 in the 4th edition.  MgO does *not* crystallize in the rutile lattice (impossible), but rather the rock salt (NaCl) lattice.  Also, the bond dissociation energy of O2 is 498 kJ/mol, not 247 kJ/mol.  (They seem to be giving it as if they'd already multiplied it by 1/2, but the phrasing of the problem makes it sound like the energy required to break one O-O double bond.)


When I use these correct pieces of information, I get a lattice energy of -3932 kJ/mol and an enthalpy of formation of -854 kJ/mol - both numbers are in decent agreement with the M&T answer key.  (At least the answer key seems to have found the errors in the problem!)

Mon, 03/21/2011 - 19:32 Permalink
Joanne Stewart / Hope College
Minor typo: Problem 10.2 part c gives a metal complex with the formula [M(CN6)]3- that should be [M(CN)6]3-.
Wed, 04/06/2011 - 23:54 Permalink
Anne Bentley / Lewis & Clark College
Exercise 7.4 has an error in the answer given at the back of the book.  The answer fails to use +1 and -1 as the Z+ and Z- values in the Born-Mayer equation, so it results in a positive lattice energy instead of a negative one.
Fri, 04/08/2011 - 13:11 Permalink
Sheila Smith / University of Michigan- Dearborn

Page 555


Fe(CO)5 + I2 --> Fe(CO)4 + CO


What happened to the I2? 

Thu, 04/21/2011 - 11:42 Permalink
Joanne Stewart / Hope College

Problem 13.4 part b. The question is asking about metal-metal bond order but it only shows one metal.

The book says: [(C5H5)Mo(CO)2]2-

 and I believe it should be: [(C5H5)Mo(CO)2]22-

Thu, 04/21/2011 - 14:52 Permalink
Adam Johnson / Harvey Mudd College


Don't thing that is a typo, though it is phrased poorly.  The first reaction is dissociation of CO with heat (which takes place in the presence of I2, or not), and the I2 comes in in the 2nd reaction:

Fe(CO)4 + I2 --> cis-I2Fe(CO)4


Thu, 04/21/2011 - 20:54 Permalink
Chip Nataro / Lafayette College


Based on previous editions (well, at least the second edition) the question shows the compound to be  [(C5H5)Mo(CO)]22-. However, the solutions manual to the second edition show the compound you formulated, [(C5H5)Mo(CO)2]22-. I like Mo being L5X2 so I have to agree with your assignment (and the solution guide). Guess that one is just destined to be a typo.

Fri, 04/22/2011 - 16:16 Permalink
Betsy Jamieson / Smith College

I believe that there is a problem with the answer to problem 9.15 (4th edition) which is very similar to problem 9-9 in the 3rd edition.  The problem asks for the most likely structure of [Co(CO)2(CN)2Br2]- if the IR spectrum has 2 CO bands and 1 CN band.  In the 3rd edition answer key, it says that the structure will have trans CN ligands and cis CO ligands.  I don't yet have an answer key for the 4th edition, but someone who has it said it was the same.

If you assume C2v symmetry for the structure with cis CO's and trans CN's, make the representations for the CO's and CN's, and reduce them, you get 2 IR symmetry allowed bands for the CO's and also for the CN's.  So, I agree with M&T on the CO's, but I think there should be 2 IR bands for the CN's.  Granted, from everything I've read on similar compounds (and I did some digging here), it seems like the symmetric stretch for the CN's will be small, but one would predict it to be allowed based on symmetry.

I need to thank Chip Nataro, Bob Linck, Maggie Geselbracht, and Adam Johnson for helpful discussions in figuring this out!


Tue, 03/06/2012 - 14:39 Permalink
Joanne Stewart / Hope College

Not sure if this is a typo or just something I don't understand. In problem 12.5, [Cr(CN)6]4- is in the column that says "Half-Lives Shorter than 1 Minute." It should be a low spin d4 complex, which according to the little table on p 445 (4th Ed) should be inert. The 2nd Edition had the same problem, and the 2nd Ed solution manual says:

Cr[(CN)6]4- is a d4 low spin species. The t2g levels are unequally occupied and the eg are vacant, which makes it a borderline complex in terms of rate.

I get that it's a Jahn-Teller ion, but only a weak one. I'm not seeing anything that would move it very far out of the "inert" category.


Thu, 04/26/2012 - 15:51 Permalink